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Question Number 135424 by benjo_mathlover last updated on 13/Mar/21
Find solution set the inequality  (√(2x−5)) + (√(25−3x)) > x
Findsolutionsettheinequality2x5+253x>x
Answered by EDWIN88 last updated on 13/Mar/21
(1) 2x−5≥0→x≥(5/2)  (2) 3x−25≤0→x≤((25)/3)  (3)(√(25−3x)) > x−(√(2x−5))   → 25−3x > x^2 −2x(√(2x−5)) +2x−5  →20−5x > x^2 −2x(√(2x−5))   →2x(√(2x−5)) > x^2 +5x−20  ⇒4x^2 −2x−5) > x^4 +25x^2 +400+10x^3 −40x^2 −200x  →x^4 +10x^3 −19x^2 −198x+405 < 0  →(x+9.21)(x+6.18)(x−2.28)(x−3.11)<0  →−9.21<x<−6.18 ∪ 2.28<x<3.11  solution set we get from (1)∩(2)∩(3)  ⇒(5/2) ≤ x < 3.11 or [ (5/2) ; 3.11 )
(1)2x50x52(2)3x250x253(3)253x>x2x5253x>x22x2x5+2x5205x>x22x2x52x2x5>x2+5x204x22x5)>x4+25x2+400+10x340x2200xx4+10x319x2198x+405<0(x+9.21)(x+6.18)(x2.28)(x3.11)<09.21<x<6.182.28<x<3.11solutionsetwegetfrom(1)(2)(3)52x<3.11or[52;3.11)

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