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Find-the-102rd-term-of-f-x-e-2x-3-at-x-0-




Question Number 6739 by Tawakalitu. last updated on 20/Jul/16
Find the 102rd term of   f(x) = e^(2x^3 )    at  x = 0
Findthe102rdtermoff(x)=e2x3atx=0
Answered by Yozzii last updated on 20/Jul/16
f(u)=e^u =Σ_(n=0) ^∞ (u^n /(n!))  ⇒T(n+1)=(u^n /(n!))   (n∈N+{0})  n+1=102⇒n=101  ∴T(102)=(u^(101) /(101!))  Let u=2x^3 . ∴ T(102)=((2^(101) x^(303) )/(101!))  At x=0, T(102)=0.  −−−−−−−−−−−−−−−−−−−−−−−−  101!=1×2×3×4×5×6×...×98×99×100×101  101!=(Π_(i=1) ^(51) (2i−1))(Π_(i=1) ^(50) 2i)  101!=2^(50) ×50!×Π_(i=1) ^(51) (2i−1)  101!=2^(50) ×2^(25) ×25!×Π_(i=1) ^(25) (2i−1)×Π_(i=1) ^(51) (2i−1)  ... omit this scribbling.
f(u)=eu=n=0unn!T(n+1)=unn!(nN+{0})n+1=102n=101T(102)=u101101!Letu=2x3.T(102)=2101x303101!Atx=0,T(102)=0.101!=1×2×3×4×5×6××98×99×100×101101!=(51i=1(2i1))(50i=12i)101!=250×50!×51i=1(2i1)101!=250×225×25!×25i=1(2i1)×51i=1(2i1)omitthisscribbling.
Commented by Tawakalitu. last updated on 20/Jul/16
Thanks so much
Thankssomuch

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