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Question Number 140615 by bramlexs22 last updated on 10/May/21
Find the area common   to the curve y^2  = 12x and  x^2 +y^2 = 24x .
Findtheareacommontothecurvey2=12xandx2+y2=24x.
Answered by EDWIN88 last updated on 10/May/21
Area = (2/3).24.12^4  + (π/2).144^(72)               = 192 + 72π
Area=23.24.124+π2.14472=192+72π
Commented by EDWIN88 last updated on 10/May/21
Commented by Dwaipayan Shikari last updated on 10/May/21
∫_0 ^(12) (√(12x)) dx=((2(√(12)))/3)(12(√(12)))=96 (Half part in positive half)  x^2 −24x+y^2 =0⇒(x−12)^2 +y^2 =12^2   Other half =(π/4)(12)^2 =36π  Total Area in enclosed in two halves =2(96+36π)=192+72π
01212xdx=2123(1212)=96(Halfpartinpositivehalf)x224x+y2=0(x12)2+y2=122Otherhalf=π4(12)2=36πTotalAreainenclosedintwohalves=2(96+36π)=192+72π

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