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Question Number 9731 by tawakalitu last updated on 29/Dec/16
Find the asymptotes of the hypebola whose  equation is given by.  (x/(24)) − (y/(29)) = 1
Findtheasymptotesofthehypebolawhoseequationisgivenby.x24y29=1
Commented by geovane10math last updated on 29/Dec/16
((29x − 24y)/(696)) = 1  29x − 24y = 696  29x − 696 = 24y  y = ((29x − 696)/(24)) = ((29x)/(24)) − 29  y is a function f(x) = ax + b , a = ((29)/(24)) and   b = −29
29x24y696=129x24y=69629x696=24yy=29x69624=29x2429yisafunctionf(x)=ax+b,a=2924andb=29
Answered by sandy_suhendra last updated on 29/Dec/16
the equation of hyperbola ≡(((x−h)^2 )/a^2 )−(((y−k)^2 )/b^2 )=1  the centre of hyperbola =(h,k)=(0,0)  a^2 =24 ⇒ a=2(√6)  b^2 =29 ⇒ b=(√(29))  the equation of hyperbola asymtotes : y=±(b/a)(x−h)+k  ⇒ y=±((√(29))/(2(√6))) x  ⇒ y=±((√(174))/(12)) x
theequationofhyperbola(xh)2a2(yk)2b2=1thecentreofhyperbola=(h,k)=(0,0)a2=24a=26b2=29b=29theequationofhyperbolaasymtotes:y=±ba(xh)+ky=±2926xy=±17412x
Commented by tawakalitu last updated on 29/Dec/16
i really appreciate sir. God bless you.
ireallyappreciatesir.Godblessyou.

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