find-the-equation-of-circle-whose-parametric-form-is-given-by-x-3cos-5-and-y-3sin-7-and-second-part-is-x-4cos-3-and-y-4sin-4-find-centre-and-radius-of-above-circle-guys-plz-ans-me-soon

Question Number 1012 by rpatle69@gmail.com last updated on 13/May/15

f i n d t h e e q u a t i o n o f c i r c l e w h o s e

p a r a m e t r i c f o r m i s g i v e n b y

x = 3 \cos θ + 5 a n d y = 3 \sin θ - 7 a n d

s e c o n d p a r t i s x = 4 \cos θ - 3 a n d

y = 4 \sin θ + 4 . f i n d c e n t r e a n d

r a d i u s o f a b o v e c i r c l e .

g u y s p l z a n s . m e s o o n \dots . .

Answered by sudhanshur last updated on 13/May/15

x - 5 = 3 \cos θ

y + 7 = 3 \sin θ

s q u a r e a n d a d d

{(x - 5)}^{2} + {(y + 7)}^{2} = 9

Answered by sudhanshur last updated on 13/May/15

x + 3 = 4 \cos θ

y - 4 = 4 \sin θ

{(x + 3)}^{2} + {(y - 4)}^{2} = 16