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Question Number 139024 by bramlexs22 last updated on 21/Apr/21
Find the exact value of cos (π/5)
Findtheexactvalueofcosπ5
Commented by EDWIN88 last updated on 21/Apr/21
 (((√5)+1)/4)
5+14
Answered by Dwaipayan Shikari last updated on 21/Apr/21
sin(π/(10))=(((√5)−1)/4)     cos((π/5))=1−2sin^2 (π/(10))=1−2(((6−2(√5))/(16)))=(((√5)+1)/4)=(φ/2)
sinπ10=514cos(π5)=12sin2π10=12(62516)=5+14=ϕ2
Answered by MJS_new last updated on 21/Apr/21
cos (π/5) +i sin (π/5) =e^((iπ)/5)  is a solution of  x^5 +1=0  (x+1)(x^4 −x^3 +x^2 −x+1)=0  x_1 =−1  x^4 −x^3 +x^2 −x+1=0  (x^2 −((1−(√5))/2)x+1)(x^2 −((1+(√5))/2)x+1)=0  x_(2, 3) =((1−(√5))/4)±((√(10+2(√5)))/4)i  x_(4, 5) =((1+(√5))/4)±((√(10−2(√5)))/4)i  cos (π/5) >0 ⇒ cos (π/5) =((1+(√5))/4)
cosπ5+isinπ5=eiπ5isasolutionofx5+1=0(x+1)(x4x3+x2x+1)=0x1=1x4x3+x2x+1=0(x2152x+1)(x21+52x+1)=0x2,3=154±10+254ix4,5=1+54±10254icosπ5>0cosπ5=1+54

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