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Find-the-Integration-Value-1-x-d-x-1-3-x-2-dx-x-1-2-x-1-4-




Question Number 140330 by Satyendra last updated on 06/May/21
Find the Integration Value:  1  ∫(((√x)d(x))/(1+^3 (√x)))=?  2 ∫(dx/(x^(1/2) −x^(1/4) ))=?
FindtheIntegrationValue:1xd(x)1+3x=?2dxx12x14=?
Answered by john_santu last updated on 06/May/21
(1) let x = t^6  →dx = 6t^5  dt  I= ∫ (t^3 /(1+t^2 )) (6t^5  dt )  I= ∫ ((6t^8 )/(1+t^2 )) dt .  now it easy to solve
(1)letx=t6dx=6t5dtI=t31+t2(6t5dt)I=6t81+t2dt.nowiteasytosolve
Answered by benjo_mathlover last updated on 06/May/21
(2) I= ∫ (dx/( (√x)−(x)^(1/4) ))   let x = z^4  →dx = 4z^3  dz  I= ∫ ((4z^3 )/(z^2 −z)) dz = ∫ ((4z^2 )/(z−1)) dz   use partial fraction
(2)I=dxxx4letx=z4dx=4z3dzI=4z3z2zdz=4z2z1dzusepartialfraction

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