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find-the-lowest-number-between-200-and-500-which-leaves-a-remainder-of-3-in-each-case-which-will-divisible-by-8-10-12-and-30-




Question Number 135990 by zakirullah last updated on 17/Mar/21
     find the lowest number between 200 and 500 which       leaves a remainder of 3 in each case      which will divisible by 8 , 10, 12 and 30?
findthelowestnumberbetween200and500whichleavesaremainderof3ineachcasewhichwilldivisibleby8,10,12and30?
Answered by Olaf last updated on 17/Mar/21
N = 8k+3 = 10l+3 = 12m+3 = 30n+3  200≤N≤500 ⇒ 7≤n≤16    12m+3 = 30n+3 ⇒ 5n = 2m  ⇒ n∈{8, 10,12, 14, 16}    N_(min)  = 30.8+3 = 243 = 12.20+3 = 10.24+3 = 8.30+3
N=8k+3=10l+3=12m+3=30n+3200N5007n1612m+3=30n+35n=2mn{8,10,12,14,16}Nmin=30.8+3=243=12.20+3=10.24+3=8.30+3
Commented by zakirullah last updated on 18/Mar/21
    you are right dear sir! but how can i understand      children of class 6th.      sir can you do this on simple method?
youarerightdearsir!buthowcaniunderstandchildrenofclass6th.sircanyoudothisonsimplemethod?
Answered by mr W last updated on 18/Mar/21
LCM from 8 and 12 is 24.  LCM from 24 and 30 is 120.  such a number is a multiple of 120  plus 3, i.e. 123, 243, 363 etc.  smallest between 200 and 500 is 243.  largest between 200 and 500 is 483.
LCMfrom8and12is24.LCMfrom24and30is120.suchanumberisamultipleof120plus3,i.e.123,243,363etc.smallestbetween200and500is243.largestbetween200and500is483.
Commented by otchereabdullai@gmail.com last updated on 18/Mar/21
powerful!
powerful!
Commented by zakirullah last updated on 18/Mar/21
ok welldon
okwelldon

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