find-the-solutions-of-the-equation-in-0-pi-sin2-sec-

Question Number 73817 by Rio Michael last updated on 16/Nov/19

f i n d t h e s o l u t i o n s o f t h e e q u a t i o n

i n 0 ⩽ θ ⩽ π

s i n 2 θ = s e c θ

Answered by mr W last updated on 16/Nov/19

\sin 2 θ ⩽ 1

\sec θ ⩾ 1

\sin 2 θ = 1 \Rightarrow θ = \frac{π}{4}

\sec θ = 1 \Rightarrow θ = 0

\Rightarrow n o s o l u t i o n f o r θ s u c h t h a t \sin 2 θ = 1 a n d \sec θ = 1!

Commented by Rio Michael last updated on 16/Nov/19

t h a n k s

Commented by peter frank last updated on 16/Nov/19

t h a n k y o u