Find-the-third-degree-polynomial-which-vanishes-when-x-1-and-x-2-which-has-a-value-8-when-x-0-and-leaves-a-remainder-16-3-when-divided-by-3x-2-

Question Number 67298 by Rio Michael last updated on 25/Aug/19

F i n d t h e t h i r d d e g r e e p o l y n o m i a l w h i c h v a n i s h e s w h e n

x = - 1 a n d x = 2, w h i c h h a s a v a l u e 8 w h e n x = 0 a n d l e a v e s a r e m a i n d e r \frac{16}{3} w h e n

d i v i d e d b y 3 x + 2 .

Commented by Prithwish sen last updated on 25/Aug/19

let the polynomial be (x + 1) (x - 2) (ax - b) = 0

putting x = 0 we get b = 4

putting x = - \frac{2}{3} we get a = 3

∴ the polynomial is (x + 1) (x - 2) (3 x - 4) = 0

i . e 3 x^{3} - 7 x^{2} - 2 x + 8 = 0 please check .

Commented by Rio Michael last updated on 25/Aug/19

t h a n k s, p e r f e c t

h e l p m e s i r w i t h t h e o n e a b o v e