find-the-value-of-0-dx-x-2-2-cos-x-1- Tinku Tara June 3, 2023 Integration FacebookTweetPin Question Number 65768 by mathmax by abdo last updated on 03/Aug/19 findthevalueof∫0∞dxx2−2(cosθ)x+1 Commented by mathmax by abdo last updated on 04/Aug/19 letI=∫0∞dxx2−2xcosθ+1⇒I=∫0∞dxx2−2xcosθ+cos2θ+sin2θ=∫0∞dx(x−cosθ)2+sin2θ=x−cosθ=∣sinθ∣u∫−cosθ∣sinθ∣+∞∣sinθ∣dusin2θ(1+u2)=1∣sinθ∣[arctanu]−cosθ∣sinθ∣+∞=1∣sinθ∣{π2+arctan(cosθ∣sinθ∣)}case1sinθ>0⇒I=1sinθ{π2+arctan(1tanθ)}=1sinθ{π2+−π2−θ}case2sinθ<0⇒I=−1sinθ{π2−arctan(cosθsnθ)}=1sinθ{−π2+−π2−θ} Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: cos-1-x-3-x-1-cos-1-x-x-3-cos-1-1-y-2pi-3-find-the-value-of-y-Next Next post: let-A-n-0-pi-2-cos-n-xdx-1-calculate-A-0-A-2-and-A-3-2-calculate-A-n-interms-of-n-3-find-0-pi-2-cos-8-xdx-