find-the-value-of-x-3-x-1-2-x-2-

Question Number 8934 by j.masanja06@gmail.com last updated on 06/Nov/16

find the value of x .

3^{x + 1} = 2^{x + 2}

Answered by Rasheed Soomro last updated on 08/Nov/16

3^{x + 1} = 2^{x + 2}

3^{x} . 3 = 2^{x} . 2^{2}

\frac{3^{x}}{2^{x}} = \frac{4}{3}

{(\frac{3}{2})}^{x} = \frac{4}{3}

xlog (\frac{3}{2}) = \log (\frac{4}{3})

x = \frac{\log 4 - \log 3}{\log 3 - \log 2} \approx 0.7095

x \approx 0.7095

Commented by j.masanja06@gmail.com last updated on 07/Nov/16

sir remember that 2^{x + 2} and not 2^{x + 1}

Commented by Rasheed Soomro last updated on 07/Nov/16

Sorry for misunderstanding!

Commented by j.masanja06@gmail.com last updated on 07/Nov/16

ok sir!

Commented by j.masanja06@gmail.com last updated on 07/Nov/16

nicely sir