Find-the-volume-of-the-region-that-is-bounded-by-the-curves-y-x-3-y-8-x-0-rotated-about-x-9- Tinku Tara June 3, 2023 Integration 0 Comments FacebookTweetPin Question Number 133533 by Raxreedoroid last updated on 22/Feb/21 Findthevolumeoftheregionthatisboundedbythecurvesy=x3,y=8,x=0,rotatedaboutx=9 Answered by bemath last updated on 23/Feb/21 V=π∫80(9−y3)2dy=π∫80(81−18y1/3+y2/3)dy=π[81y−272y4/3+35y5/3]08=8π[81−272(81/3)+35(8)2/3]=8π[81−27+125]=8π[54+125]=451π15 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: find-the-sequence-u-n-wich-verify-u-n-u-n-1-1-n-n-2-n-1-Next Next post: calculate-1-2-2-x-2-3y-2-e-x-2-3y-2-dxdy- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.
![V=π∫_0 ^8 (9−(y)^(1/3) )^2 dy =π∫_0 ^8 (81−18y^(1/3) +y^(2/3) )dy =π [81y−((27)/2)y^(4/3) +(3/5)y^(5/3) ]_0 ^8 = 8π [81−((27)/2)(8^(1/3) )+(3/5)(8)^(2/3) ] = 8π [81−27+((12)/5) ] = 8π[ 54+ ((12)/5) ] = 451π (1/5)](https://www.tinkutara.com/question/Q133559.png)