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find-value-in-2-4-13-0-




Question Number 9861 by Raja Naik last updated on 09/Jan/17
find  λ value in λ^2 −4λ−13=0
$$\mathrm{find}\:\:\lambda\:\mathrm{value}\:\mathrm{in}\:\lambda^{\mathrm{2}} −\mathrm{4}\lambda−\mathrm{13}=\mathrm{0} \\ $$
Answered by FilupSmith last updated on 09/Jan/17
λ=((4±(√(16+4(13))))/2)  λ=((4±(√(68)))/2)  λ=((4±2(√(17)))/2)  λ=2±(√(17))
$$\lambda=\frac{\mathrm{4}\pm\sqrt{\mathrm{16}+\mathrm{4}\left(\mathrm{13}\right)}}{\mathrm{2}} \\ $$$$\lambda=\frac{\mathrm{4}\pm\sqrt{\mathrm{68}}}{\mathrm{2}} \\ $$$$\lambda=\frac{\mathrm{4}\pm\mathrm{2}\sqrt{\mathrm{17}}}{\mathrm{2}} \\ $$$$\lambda=\mathrm{2}\pm\sqrt{\mathrm{17}} \\ $$

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