find-value-log40-9-4log5-2log6-

Question Number 69457 by mhmd last updated on 23/Sep/19

f i n d v a l u e l o g 40 / 9 + 4 l o g 5 + 2 l o g 6 ?

Answered by MJS last updated on 23/Sep/19

\log \frac{40}{9} + 4 \log 5 + 2 \log 6 =

= \log 40 - \log 9 + 4 \log 5 + 2 \log 2 + 2 \log 3 =

= 3 \log 2 + \log 5 - 2 \log 3 + 4 \log 5 + 2 \log 2 + 2 \log 3 =

= 5 \log 2 + 5 \log 5 = 5 \log 10

Commented by kaivan.ahmadi last updated on 24/Sep/19

5 l o g 10 = 5 \times 1 = 5

Commented by MJS last updated on 24/Sep/19

not sure about the usage of “ \log^{″}

some people use “ \ln^{″} for \log_{e} and “ \log^{″} for

\log_{10}; others use “ \log^{″} for \log_{e} and “ \log_{b}^{″} for

all other bases b

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