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Question Number 4790 by Dnilka228 last updated on 10/Mar/16
Function Γ is a+b  a+b=AB  a≠b−4  b−4=4+b  b=a−1  a−1=2  b=2  a=3  Function Γ is (a/b)+sin a+b  Γ=(a/b)+sin a+b  a=b−1  b=5  a=4  9−a=b  9−b=a  Funcion Γ is ((sin a+sin b)/(sin^(−1) a+sin^(−1) b))×(a+b)  sin a+sin b<c_1   c_1 =a×3  a=b+3  b=2  b+3=2+3  2+3=5  a=5  a×3=15  c_1 =15  c_2 =c_1 ÷5  c_1 ÷5=3  c_2 =3  c_1 +c_2 =c_3   c_3 =18  c_3 ≈sin a+b  a×b×2=20  sin 20=sin a+b  c_3 ≈20
FunctionΓisa+ba+b=ABab4b4=4+bb=a1a1=2b=2a=3FunctionΓisab+sina+bΓ=ab+sina+ba=b1b=5a=49a=b9b=aFuncionΓissina+sinbsin1a+sin1b×(a+b)sina+sinb<c1c1=a×3a=b+3b=2b+3=2+32+3=5a=5a×3=15c1=15c2=c1÷5c1÷5=3c2=3c1+c2=c3c3=18c3sina+ba×b×2=20sin20=sina+bc320

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