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Generalization-of-Q-No-1296-f-x-k-f-x-n-f-x-




Question Number 1302 by Rasheed Ahmad last updated on 20/Jul/15
Generalization of Q No 1296  f(x+k)=[ f(x) ]^n   f(x)=?
$${Generalization}\:{of}\:{Q}\:{No}\:\mathrm{1296} \\ $$$${f}\left({x}+{k}\right)=\left[\:{f}\left({x}\right)\:\right]^{{n}} \\ $$$${f}\left({x}\right)=? \\ $$
Answered by prakash jain last updated on 21/Jul/15
f(x)=a^n^(x/k)    f(x+k)=a^n^(x/k+1)  =(a^n^(x/k)  )^n =(f(x))^n
$${f}\left({x}\right)={a}^{{n}^{{x}/{k}} } \\ $$$${f}\left({x}+{k}\right)={a}^{{n}^{{x}/{k}+\mathrm{1}} } =\left({a}^{{n}^{{x}/{k}} } \right)^{{n}} =\left({f}\left({x}\right)\right)^{{n}} \\ $$

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