Generalization-of-Q-No-1296-f-x-k-f-x-n-f-x-

Question Number 1302 by Rasheed Ahmad last updated on 20/Jul/15

G e n e r a l i z a t i o n o f Q N o 1296

f (x + k) = {[f (x)]}^{n}

f (x) = ?

Answered by prakash jain last updated on 21/Jul/15

f (x) = a^{n^{x / k}}

f (x + k) = a^{n^{x / k + 1}} = {(a^{n^{x / k}})}^{n} = {(f (x))}^{n}