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Give-the-result-of-the-following-computation-as-an-integer-in-the-usual-decimal-form-303-000-000-000-303-3-300-000-033-1-000-100-010-001-




Question Number 518 by Yugi last updated on 25/Jan/15
Give the result of the following computation as an integer in the usual decimal  form.                                    ((303,000,000,000,303×3,300,000,033)/(1,000,100,010,001))
Givetheresultofthefollowingcomputationasanintegerintheusualdecimalform.303,000,000,000,303×3,300,000,0331,000,100,010,001
Answered by prakash jain last updated on 22/Jan/15
((303(10^(12) +1)×33×(10^8 +1))/((10^(12) +10^8 +10^4 +1)))  =((303×33×(10^(12) +1)(10^8 +1))/([10^8 (10^4 +1)+(10^4 +1)]))  =((303×33×[(10^4 )^3 +1][10^8 +1])/((10^8 +1)(10^4 +1)))  =((303×33(10^4 +1)(10^8 −10^4 +1))/(10^4 +1))  =303×33×(10^8 −10^4 +1)  =9999×(99990000+1)  =9999×9999×10000+9999  =(10000−1)^2 ×10000+9999  =(100000000−20000+1)×10000+9999  =(99980000+1)×10000+9999  =999800010000+9999  =999800019999
303(1012+1)×33×(108+1)(1012+108+104+1)=303×33×(1012+1)(108+1)[108(104+1)+(104+1)]=303×33×[(104)3+1][108+1](108+1)(104+1)=303×33(104+1)(108104+1)104+1=303×33×(108104+1)=9999×(99990000+1)=9999×9999×10000+9999=(100001)2×10000+9999=(10000000020000+1)×10000+9999=(99980000+1)×10000+9999=999800010000+9999=999800019999

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