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Given-a-b-5ab-b-c-7bc-c-a-6ac-where-a-b-c-0-Find-abc-




Question Number 134912 by bramlexs22 last updated on 08/Mar/21
Given  { ((a+b=5ab)),((b+c=7bc)),((c+a=6ac)) :}  where a,b,c ≠ 0.  Find abc
Given{a+b=5abb+c=7bcc+a=6acwherea,b,c0.Findabc
Answered by Ñï= last updated on 08/Mar/21
(1/a)+(1/b)=5⇔A+B=5  (1/b)+(1/c)=7⇔B+C=7  (1/a)+(1/c)=6⇔A+C=6  ⇒A=2    B=3   C=4  ⇒  abc=(1/(ABC))=(1/(24))
1a+1b=5A+B=51b+1c=7B+C=71a+1c=6A+C=6A=2B=3C=4abc=1ABC=124
Commented by Rasheed.Sindhi last updated on 10/Mar/21
Nice sir!
Nicesir!

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