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Given-a-b-and-c-are-real-numbers-and-a-lt-b-lt-c-If-1-a-1-b-1-c-1-18-find-minimum-value-of-a-




Question Number 134069 by john_santu last updated on 27/Feb/21
Given a,b and c are real numbers and a<b<c.  If (1/a) + (1/b) + (1/c) = (1/(18)) , find minimum value of a.
Givena,bandcarerealnumbersanda<b<c.If1a+1b+1c=118,findminimumvalueofa.
Commented by mr W last updated on 27/Feb/21
no minimum for a exists.
nominimumforaexists.
Commented by mr W last updated on 27/Feb/21
a=(1/((1/(18))−((1/b)+(1/c)))) →18 if b, c →+∞  a=(1/((1/(18))−((1/b)+(1/c)))) →−∞ if b, c →0^+
a=1118(1b+1c)18ifb,c+a=1118(1b+1c)ifb,c0+
Answered by bramlexs22 last updated on 27/Feb/21
 AM−GM   (((1/a)+(1/b)+(1/c))/(3 )) ≥ ((1/(abc)))^(1/3)    (([ (1/(18)) ])/3) ≥ ((1/(abc)))^(1/3)  ⇒ (1/(54)) ≥ ((1/(abc)))^(1/3)   (1/(54^3 )) ≥ (1/(abc)) , it hold for a=b=c  we get a = 54
AMGM1a+1b+1c31abc3[118]31abc31541abc315431abc,itholdfora=b=cwegeta=54
Commented by mr W last updated on 27/Feb/21
what do you get if b=c=1000000?  what do you get if b=c=1/1000000?
whatdoyougetifb=c=1000000?whatdoyougetifb=c=1/1000000?

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