Given-a-curve-y-1-x-2-1-Find-the-equation-of-tangent-line-with-have-slope-of-tangent-minimum- Tinku Tara June 3, 2023 Differentiation 0 Comments FacebookTweetPin Question Number 138085 by liberty last updated on 10/Apr/21 Givenacurvey=1x2+1.Findtheequationoftangentlinewithhaveslopeoftangentminimum. Answered by EDWIN88 last updated on 10/Apr/21 lettheeqoftangentlineisy=px+qwherep=minimumvalueofy′step(1)y=(x2+1)−1;y′=−2x(x2+1)−2wewantp(x)=−2x(x2+1)2minimump′(x)=−2(x2+1)2−(−2x)(4x)(x2+1)(x2+1)4p′(x)=−2(x2+1)+8x2(x2+1)3=0;p′(x)=6x2−2(x2+1)3⇒6x2=2;x2=13orx=±33chekp″(x)=12x(x2+1)3−6x(6x2−2)(x2+1)2(x2+1)6p″(x)=24x(1−x2)(x2+1)4>0whenx=13sominimumofp(x)whenx=13thenp=−2(13)169=−233×916=−338(2)contactpointoftangent(13,34)thuseqoftangentlinehavetheminimumslopeofcurvey=1x2+1is33x+8y=33(13)+8(34)33x+8y=9 Commented by EDWIN88 last updated on 10/Apr/21 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 0-pi-2-ln-ln-2-sin-pi-2-ln-2-sin-ln-cos-tan-d-Next Next post: 2x-2-1-x-4-dx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.