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Given-a-function-f-where-f-x-0for-x-R-If-the-area-U-x-y-0-2y-f-x-6-x-2-is-u-and-the-area-V-x-y-0-y-f-x-2-x-0-is-v-then-what-the-value-of-1-2-4x-f-2x-2-8-dx-A-5u-4v-




Question Number 138611 by liberty last updated on 15/Apr/21
Given a function f where   f(x)≥ 0for ∀x∈R. If the area  U = { (x,y)∣0≤2y≤f(x), −6≤x≤−2}  is u and the area V={(x,y)∣0≤y≤f(x),−2≤x≤0}  is v then what the value of  ∫_1 ^2  4x f(2x^2 −8) dx .  (A) 5u+4v     (D)2u+v  (B) 4u+3v    (E) u+v  (C) 3u+2v
Givenafunctionfwheref(x)0forxR.IftheareaU={(x,y)02yf(x),6x2}isuandtheareaV={(x,y)0yf(x),2x0}isvthenwhatthevalueof214xf(2x28)dx.(A)5u+4v(D)2u+v(B)4u+3v(E)u+v(C)3u+2v
Answered by ajfour last updated on 15/Apr/21
u=(1/2)∫_(−6) ^( −2) f(x)dx=((F(−2)−F(−6))/2)  v=∫_(−2) ^( 0) f(x)dx=F(0)−F(−2)  I=∫_1 ^( 2) 4xf(2x^2 −8)dx  let  2x^2 −8=t  ⇒   4xdx=dt  I=∫_(−6) ^( 0) f(x)dx=F(0)−F(−6)   = 2u+v    (D) .
u=1262f(x)dx=F(2)F(6)2v=20f(x)dx=F(0)F(2)I=124xf(2x28)dxlet2x28=t4xdx=dtI=60f(x)dx=F(0)F(6)=2u+v(D).
Answered by tepebea last updated on 16/Apr/21
mantap...
mantap
Commented by ajfour last updated on 16/Apr/21
what does this mean in English..
whatdoesthismeaninEnglish..
Commented by tepebea last updated on 16/Apr/21
good job or that′s great
goodjoborthatsgreat

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