given-a-n-and-b-n-two-real-sequence-can-a-serie-n-1-a-n-and-n-1-b-n-diverge-but-n-1-a-n-b-n-converge-

Question Number 476 by 123456 last updated on 11/Jan/15

g i v e n a_{n} a n d b_{n} t w o r e a l s e q u e n c e

c a n a s e r i e \underset{n = 1}{\sum^{+ \infty}} a_{n} a n d \underset{n = 1}{\sum^{+ \infty}} b_{n} d i v e r g e

b u t

\underset{n = 1}{\sum^{+ \infty}} (a_{n} + b_{n}) c o n v e r g e ?

Commented by prakash jain last updated on 11/Jan/15

a_{n} = 2^{n}

b_{n} = - 2^{n}