Given-that-p-n-16p-express-log-2-p-in-terms-of-n-

Question Number 5580 by Rasheed Soomro last updated on 21/May/16

Given that p^{n} = 16 p, express \log_{2} p

in terms of n .

Answered by FilupSmith last updated on 21/May/16

p^{n} = 16 p

p^{n - 1} = 16

(n - 1) \log_{2} p = \log_{2} (2^{4})

\log_{2} p = \frac{4}{n - 1}