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given-the-function-y-1-x-2-1-The-tangent-equation-of-the-curve-with-the-smallest-gradient-is-




Question Number 77271 by jagoll last updated on 05/Jan/20
given the function  y = (1/(x^2 +1)). The tangent equation  of the curve with the smallest   gradient is ..
$$\mathrm{given}\:\mathrm{the}\:\mathrm{function} \\ $$$$\mathrm{y}\:=\:\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{2}} +\mathrm{1}}.\:\mathrm{The}\:\mathrm{tangent}\:\mathrm{equation} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{curve}\:\mathrm{with}\:\mathrm{the}\:\mathrm{smallest}\: \\ $$$$\mathrm{gradient}\:\mathrm{is}\:.. \\ $$

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