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How-do-I-find-the-sum-of-1-3x-6x-2-10x-3-15x-4-where-1-lt-x-lt-1-Please-Help-




Question Number 136161 by nimnim last updated on 19/Mar/21
How do I find the sum of    1+3x+6x^2 +10x^3 +15x^4 +.......∞,  where −1<x<1 ?    Please Help..
HowdoIfindthesumof1+3x+6x2+10x3+15x4+.,where1<x<1?PleaseHelp..
Answered by bramlexs22 last updated on 19/Mar/21
S = 1+3x+6x^2 +10x^3 +15x^4 +...  xS=x+3x^2 +6x^3 +10x^4 +...  (1−x)S=1+2x+3x^2 +4x^3 +5x^4 +...  let T = 1+2x+3x^2 +4x^3 +5x^4 +...  ∫ T dx = x+x^2 +x^3 +x^4 +x^5 +...  ∫T dx = (x/(1−x)) then T=(1/((1−x)^2 ))  so S = (1/((1−x)^3 ))
S=1+3x+6x2+10x3+15x4+xS=x+3x2+6x3+10x4+(1x)S=1+2x+3x2+4x3+5x4+letT=1+2x+3x2+4x3+5x4+Tdx=x+x2+x3+x4+x5+Tdx=x1xthenT=1(1x)2soS=1(1x)3
Commented by nimnim last updated on 19/Mar/21
Thank you Sir.
ThankyouSir.

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