Menu Close

How-many-geometric-progressions-is-are-possible-contauning-27-8-and-12-as-three-of-its-their-terms-a-1-b-2-c-4-d-infinitely-many-




Question Number 12304 by Gaurav3651 last updated on 18/Apr/17
How many geometric progressions  is/are possible contauning 27,8  and 12 as three of its/their terms?  (a)  1  (b)  2  (c)  4  (d)  infinitely many
Howmanygeometricprogressionsis/arepossiblecontauning27,8and12asthreeofits/theirterms?(a)1(b)2(c)4(d)infinitelymany
Answered by mrW1 last updated on 18/Apr/17
let′s assume 8, 12 and 27 are 3 terms of  a GP with the common ratio q:  8...(n−1 terms)...12....(m−1 terms)...27    ((27)/(12))=((3×3×3)/(3×2×2))=((3×3)/(2×2))=q^m         (i)  ((12)/8)=((2×2×3)/(2×2×2))=(3/2)=q^n              (ii)  q^(m−n) =(3/2)         (i)/(ii)  ⇒ q=((3/2))^(1/(m−n))   q^n =((3/2))^(n/(m−n)) =(3/2)         from (ii)  ⇒ (n/(m−n))=1  n=m−n  ⇒ m=2n  ⇒ q=((3/2))^(1/n)       from (ii)  i.e.  for any n≥1 we can always find  a GP  whose 1st term is 8, (1+n)−th   term is 12 and (1+3n)−th term is 27,  and their common ratio is q=((3/2))^(1/n) :  T_1 =8  ..... (n−1 terms between)  T_(1+n) =8×q^n =8×((3/2))^(n/n) =12  ..... (2n−1 terms between)  T_(1+3n) =8×q^(3n) =8×((3/2))^((3n)/n) =8×((3/2))^3 =27     since any n≥1 fulfills this, we have  infinitely many such GP.    ⇒ Answer (d) is correct.    Examples  n=1:  8,12,18,27.....    n=2:  8,8×((3/2))^(1/2) ,12,12×((3/2))^(1/2) ,18,18×((3/2))^(1/2) ,27....    n=3:  8,8×((3/2))^(1/3) ,8×((3/2))^(2/3) ,12,12×((3/2))^(1/3) ,12×((3/2))^(2/3) ,18,18×((3/2))^(1/3) ,18×((3/2))^(2/3) ,27....
letsassume8,12and27are3termsofaGPwiththecommonratioq:8(n1terms)12.(m1terms)272712=3×3×33×2×2=3×32×2=qm(i)128=2×2×32×2×2=32=qn(ii)qmn=32(i)/(ii)q=(32)1mnqn=(32)nmn=32from(ii)nmn=1n=mnm=2nq=(32)1nfrom(ii)i.e.foranyn1wecanalwaysfindaGPwhose1sttermis8,(1+n)thtermis12and(1+3n)thtermis27,andtheircommonratioisq=(32)1n:T1=8..(n1termsbetween)T1+n=8×qn=8×(32)nn=12..(2n1termsbetween)T1+3n=8×q3n=8×(32)3nn=8×(32)3=27sinceanyn1fulfillsthis,wehaveinfinitelymanysuchGP.Answer(d)iscorrect.Examplesn=1:8,12,18,27..n=2:8,8×(32)12,12,12×(32)12,18,18×(32)12,27.n=3:8,8×(32)13,8×(32)23,12,12×(32)13,12×(32)23,18,18×(32)13,18×(32)23,27.

Leave a Reply

Your email address will not be published. Required fields are marked *