How-many-geometric-progressions-is-are-possible-contauning-27-8-and-12-as-three-of-its-their-terms-a-1-b-2-c-4-d-infinitely-many- Tinku Tara June 3, 2023 Others 0 Comments FacebookTweetPin Question Number 12304 by Gaurav3651 last updated on 18/Apr/17 Howmanygeometricprogressionsis/arepossiblecontauning27,8and12asthreeofits/theirterms?(a)1(b)2(c)4(d)infinitelymany Answered by mrW1 last updated on 18/Apr/17 let′sassume8,12and27are3termsofaGPwiththecommonratioq:8…(n−1terms)…12….(m−1terms)…272712=3×3×33×2×2=3×32×2=qm(i)128=2×2×32×2×2=32=qn(ii)qm−n=32(i)/(ii)⇒q=(32)1m−nqn=(32)nm−n=32from(ii)⇒nm−n=1n=m−n⇒m=2n⇒q=(32)1nfrom(ii)i.e.foranyn⩾1wecanalwaysfindaGPwhose1sttermis8,(1+n)−thtermis12and(1+3n)−thtermis27,andtheircommonratioisq=(32)1n:T1=8…..(n−1termsbetween)T1+n=8×qn=8×(32)nn=12…..(2n−1termsbetween)T1+3n=8×q3n=8×(32)3nn=8×(32)3=27sinceanyn⩾1fulfillsthis,wehaveinfinitelymanysuchGP.⇒Answer(d)iscorrect.Examplesn=1:8,12,18,27…..n=2:8,8×(32)12,12,12×(32)12,18,18×(32)12,27….n=3:8,8×(32)13,8×(32)23,12,12×(32)13,12×(32)23,18,18×(32)13,18×(32)23,27…. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: What-is-1-3-1-x-4-dx-equal-to-a-232-5-b-116-5-c-116-5-d-232-5-Next Next post: If-c-gt-0-and-4a-c-lt-2b-then-ax-2-bx-c-0-has-a-root-in-which-intervals-a-0-2-b-2-3-c-3-4-d-2-0- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.