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Question Number 4724 by 123456 last updated on 29/Feb/16
how the gravity work on a R^4  universe?  does any R^3  people will be atracted by  some “ghost” object?
howthegravityworkonaR4universe?doesanyR3peoplewillbeatractedbysomeghostobject?
Commented by Yozzii last updated on 29/Feb/16
R^4  is the domain giving the field F  of positions u=(a_1 ,a_2 ,a_3 ,a_4 ) in   4−dimensional space. Gravity g is a  vector which hence must be able to  act along any straight line in F. We  can write g=(g_1 (a_1 ),g_2 (a_2 ),g_3 (a_3 ),g_4 (a_4 ))  where g_i    (1≤i≤4) are gravitational  force functions of position relative to a  body of mass M. In R^3  gravity is  dependent on the masses m_i  involved  and position. We′d then expect that  g_i  are dependent on the positions of  bodies and their masses. Rewriting g  we have   g= (((g_1 (m,M,a_1 ,b_1 ))),((g_2 (m,M,a_2 ,b_2 ))),((g_3 (m,M,a_3 ,b_3 ))),((g_4 (m,M,a_4 ,b_4 ))) )  .
R4isthedomaingivingthefieldFofpositions\boldsymbolu=(a1,a2,a3,a4)in4dimensionalspace.Gravity\boldsymbolgisavectorwhichhencemustbeabletoactalonganystraightlineinF.Wecanwrite\boldsymbolg=(g1(a1),g2(a2),g3(a3),g4(a4))wheregi(1i4)aregravitationalforcefunctionsofpositionrelativetoabodyofmassM.InR3gravityisdependentonthemassesmiinvolvedandposition.Wedthenexpectthatgiaredependentonthepositionsofbodiesandtheirmasses.Rewriting\boldsymbolgwehave\boldsymbolg=(g1(m,M,a1,b1)g2(m,M,a2,b2)g3(m,M,a3,b3)g4(m,M,a4,b4)).

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