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Question Number 134746 by zahaku last updated on 06/Mar/21
How to calculate  lim_(x→−3) ((x+3)/( (√(∣x^2 +x−6∣))))    ?
Howtocalculatelimx3x+3x2+x6?
Answered by mathmax by abdo last updated on 06/Mar/21
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Answered by EDWIN88 last updated on 07/Mar/21
lim_(x→−3)  (((x+3))/( (√(∣(x+3)(x−2)∣)))) = lim_(x→−3)  (1/( (√(2−x)))) .lim_(x→−3)  (((x+3))/( (((x+3)^2 ))^(1/4) ))  = (1/( (√5))).lim_(x→−3) (√(x+3)) = 0
limx3(x+3)(x+3)(x2)=limx312x.limx3(x+3)(x+3)24=15.limx3x+3=0

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