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Question Number 76290 by benjo last updated on 26/Dec/19
how to prove x^y  +y^x  ≥1 , x,y ∈R  x,y > 0
howtoprovexy+yx1,x,yRx,y>0
Commented by MJS last updated on 26/Dec/19
we can exchange x and y ⇒ let x≤y  it′s easy for these cases  (1) x=y  (2) 1≤x<y<∞  (3) 0<x≤1<y<∞  I found no proper way for  (4) 0<x<y<1
wecanexchangexandyletxyitseasyforthesecases(1)x=y(2)1x<y<(3)0<x1<y<Ifoundnoproperwayfor(4)0<x<y<1
Answered by mind is power last updated on 26/Dec/19
x=y=−3 false
x=y=3false
Commented by benjo last updated on 26/Dec/19
sir x >0 and y>0
sirx>0andy>0

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