i-n-1-3i-1-2-3-n-1-i-0- Tinku Tara June 3, 2023 Algebra 0 Comments FacebookTweetPin Question Number 6354 by sanusihammed last updated on 24/Jun/16 i=n−1Σ3i=12(3n−1)i=0 Commented by nburiburu last updated on 24/Jun/16 doesn′tseemwellwriten:∑n−1i=03i=3.∑n−1i=0i=3.n(n−1)/2sointhewayitiswrittenitisFALSE. Commented by prakash jain last updated on 24/Jun/16 ∑n−1i=03i≠12(3n−1)n=3LHS=0+3+6=9RHS=12(33−1)=13Theformulaiscorrectifthequestionis∑n−1i=03iprovingforn=k+1assumingresultforn=k12(3k−1)+=12[3k−1+2⋅3k]=13[3k(2+1)−1]=12(3k+1−1) Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 1-2-3-2-5-2-2n-1-2-n-3-4n-2-1-Next Next post: A-nuclide-81-210-X-decays-to-another-nuclide-80-A-Y-in-four-successive-radioactive-decays-Each-decay-involves-the-emmision-of-either-an-alpha-particle-or-a-beta-particle-The-value-of-A-is- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.