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If-12-x-y-and-4-provides-a-sequence-such-that-the-first-3-of-the-numbers-are-in-arithmetic-progression-Calculate-the-a-Possible-values-of-x-and-y-b-The-sum-of-the-A-P-c-The-product-of-the-la




Question Number 10318 by Tawakalitu ayo mi last updated on 03/Feb/17
If 12, x, y and 4 provides a sequence such that  the first 3 of the numbers are in arithmetic  progression. Calculate the   (a) Possible values of x and y  (b) The sum of the A.P  (c) The product of the last 3 numbers of  the G.P
If12,x,yand4providesasequencesuchthatthefirst3ofthenumbersareinarithmeticprogression.Calculatethe(a)Possiblevaluesofxandy(b)ThesumoftheA.P(c)Theproductofthelast3numbersoftheG.P
Answered by mrW1 last updated on 05/Feb/17
(a)  the first 3 numbers are in A.P.  ⇒ y−x=x−12     (i)  the last 3 numbers are in G.P.:  ⇒(4/y)=(y/x)     (ii)    from (i) we get:  y=2x−12=2(x−6)    from (ii) we get:  y^2 =4x  4(x^2 −12x+36)=4x  x^2 −13x+36=0  x=((13±(√(13^2 −4×36)))/2)=((13±5)/2)= { (9),(4) :}  y=2(x−6)= { (6),((−4)) :}    the sequence is  12, 9, 6, 4 or  12, 4, −4, 4    (b)  12+9+6=27 or  12+4−4=12    (c)  9×6×4=216 or  4×(−4)×4=−64
(a)thefirst3numbersareinA.P.yx=x12(i)thelast3numbersareinG.P.:4y=yx(ii)from(i)weget:y=2x12=2(x6)from(ii)weget:y2=4x4(x212x+36)=4xx213x+36=0x=13±1324×362=13±52={94y=2(x6)={64thesequenceis12,9,6,4or12,4,4,4(b)12+9+6=27or12+44=12(c)9×6×4=216or4×(4)×4=64
Commented by Tawakalitu ayo mi last updated on 04/Feb/17
I really appreciate your effort sir. God bless  you sir.
Ireallyappreciateyoureffortsir.Godblessyousir.

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