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If-270-lt-x-lt-360-simplify-2-2-2cosx-




Question Number 8306 by lepan last updated on 07/Oct/16
If 270°<x<360°, simplify  (√(2+(√(2+2cosx)))).
If270°<x<360°,simplify2+2+2cosx.
Commented by sou1618 last updated on 07/Oct/16
(√(2+(√(2+2cosx)))) (270°<x<360°)  2cos^2 α=1+cos2α  =(√(2+(√(4cos^2 ((1/2)x)))))  =(√(2+∣2cos((1/2)x)∣))  135°<(1/2)x<180° ⇒ cos((1/2)x)<0  =(√(2−2cos((1/2)x)))  2sin^2 α=1−cos2α  =(√(4sin^2 ((1/4)x)))  =∣2sin((1/4)x)∣  67.5°<(1/4)x<90° ⇒ sin((1/4)x)>0  =2sin(1/4)x
2+2+2cosx(270°<x<360°)2cos2α=1+cos2α=2+4cos2(12x)=2+2cos(12x)135°<12x<180°cos(12x)<0=22cos(12x)2sin2α=1cos2α=4sin2(14x)=∣2sin(14x)67.5°<14x<90°sin(14x)>0=2sin14x

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