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If-3-log-3-7-x-7-log-7-3-x-then-the-value-of-x-will-be-




Question Number 138091 by liberty last updated on 10/Apr/21
If 3^((log _3  7)^x )  = 7^((log _7  3)^x )  , then the  value of x will be …
If3(log37)x=7(log73)x,thenthevalueofxwillbe
Answered by mitica last updated on 10/Apr/21
(log_3 7)^x =a⇒(log_7 3)^x =(1/a)  3^a =7^(1/a) ⇒a=log_3 7^(1/a) ⇒a=(log_3 7)^(1/2) ⇒x=(1/2)
(log37)x=a(log73)x=1a3a=71aa=log371aa=(log37)12x=12
Answered by Ankushkumarparcha last updated on 10/Apr/21
Solution: Taking ′log_e ′ on both sides.  (log_3 7)^x log_e (3) = (log_7 3)^x log_e (7)  (((log_3 7)/(log_7 3)))^x = ((log_e 7)/(log_e 3)) ,  (((log_e 7)/(log_e 3)))^(2x) = ((log_e 7)/(log_e 3))  ( ∵ log_a b = ((log_e b)/(log_e a)))  By comparing.We get,  x= 1/2
Solution:Takinglogeonbothsides.(log37)xloge(3)=(log73)xloge(7)(log37log73)x=loge7loge3,(loge7loge3)2x=loge7loge3(logab=logeblogea)Bycomparing.Weget,x=1/2

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