Question Number 132550 by liberty last updated on 15/Feb/21
$$\mathrm{If}\:{a}=\mathrm{1}\:\mathrm{then}\:\underset{{x}\rightarrow\left({a}^{\mathrm{2}} −\mathrm{3}{x}+\mathrm{5}\right)} {\mathrm{lim}}\frac{−\mathrm{4}{x}^{\mathrm{2}} +\sqrt{\mathrm{3}{x}+\mathrm{1}}}{\:\sqrt{{x}^{\mathrm{2}} +\mathrm{8}{x}}+\mathrm{2}}\:=? \\ $$$$\left(\mathrm{a}\right)\:−\mathrm{1}\:\:\:\:\:\:\:\left(\mathrm{b}\right)\:−\frac{\mathrm{4}}{\mathrm{5}}\:\:\:\:\:\:\:\left(\mathrm{c}\right)\:−\frac{\mathrm{3}}{\mathrm{5}} \\ $$$$\left(\mathrm{d}\right)\:−\frac{\mathrm{2}}{\mathrm{5}}\:\:\:\:\left(\mathrm{e}\right)\:−\frac{\mathrm{1}}{\mathrm{5}} \\ $$
Commented by MJS_new last updated on 15/Feb/21
$${x}\rightarrow\left({a}^{\mathrm{2}} −\mathrm{3}{x}+\mathrm{5}\right)\:??? \\ $$
Commented by liberty last updated on 15/Feb/21
$$\mathrm{yes}\:\mathrm{sir}.\:\mathrm{i}\:\mathrm{don}'\mathrm{t}\:\mathrm{have}\:\mathrm{the}\:\mathrm{answer} \\ $$
Commented by MJS_new last updated on 15/Feb/21
$$\mathrm{how}\:\mathrm{can}\:\mathrm{we}\:\mathrm{have}\:{x}\rightarrow−\mathrm{3}{x}+\mathrm{6}\:\mathrm{other}\:\mathrm{than} \\ $$$${x}=−\mathrm{3}{x}+\mathrm{6}\:\Rightarrow\:{x}=\frac{\mathrm{3}}{\mathrm{2}}? \\ $$$$\mathrm{in}\:\mathrm{this}\:\mathrm{case}\:\mathrm{the}\:\mathrm{limit}\:\mathrm{is}\:\mathrm{trivial} \\ $$
Commented by liberty last updated on 15/Feb/21
$$\mathrm{i}\:\mathrm{think}\:\mathrm{this}\:\mathrm{question}\:\mathrm{error}\:\mathrm{sir} \\ $$
Answered by guyyy last updated on 20/Feb/21
