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if-a-b-c-gt-0-then-9abc-a-3-b-3-c-3-a-2-bc-b-2-ca-c-2-ab-6-




Question Number 144083 by mathdanisur last updated on 21/Jun/21
if  a;b;c>0  then:  ((9abc)/(a^3  + b^3  + c^3 )) + (a^2 /(bc)) + (b^2 /(ca)) + (c^2 /(ab)) ≥ 6
ifa;b;c>0then:9abca3+b3+c3+a2bc+b2ca+c2ab6
Answered by mitica last updated on 21/Jun/21
((9abc)/(a^3 +b^3 +c^3 ))+(a^2 /(bc))+(b^2 /(ac))+(c^2 /(ab))=((9abc)/(a^3 +b^3 +c^3 ))+((a^3 +b^3 +c^3 )/(abc)) ≥^(am−gm)   2(√(((9abc)/(a^3 +b^3 +c^3 ))∙((a^3 +b^3 +c^3 )/(abc))))=2∙3=6
9abca3+b3+c3+a2bc+b2ac+c2ab=9abca3+b3+c3+a3+b3+c3abcamgm29abca3+b3+c3a3+b3+c3abc=23=6
Commented by mathdanisur last updated on 21/Jun/21
alot cool thanks Sir
alotcoolthanksSir

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