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Question Number 72496 by Shamim last updated on 29/Oct/19
if a^x =b, b^y =c, c^z =a then prove that,  xyz=0.
ifax=b,by=c,cz=athenprovethat,xyz=0.
Answered by som(math1967) last updated on 29/Oct/19
a^x =b ⇒a^(xy) =b^y   a^(xy) =c⇒a^(xyz) =c^z   ∴a^(xyz) =a ∴xyz=1   so I think it should be xyz=1
ax=baxy=byaxy=caxyz=czaxyz=axyz=1soIthinkitshouldbexyz=1
Answered by Tanmay chaudhury last updated on 29/Oct/19
a=c^z   a=(b^y )^z =b^(yz)   a=(a^x )^(yz) =a^(xyz) →so xyz=1
a=cza=(by)z=byza=(ax)yz=axyzsoxyz=1

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