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Question Number 3317 by rishabh last updated on 10/Dec/15
If cosec θ, sec θ, and cot θ are in H.P., then  ((sin θ+tan θ)/(cos θ)) = ?
Ifcosecθ,secθ,andcotθareinH.P.,thensinθ+tanθcosθ=?
Answered by prakash jain last updated on 10/Dec/15
(2/(sec θ))=(1/(cosec θ))+(1/(cot θ))=sin θ+tan θ  2cos θ=sin θ+tan θ  ((sin θ+tan θ)/(cos θ))=2
2secθ=1cosecθ+1cotθ=sinθ+tanθ2cosθ=sinθ+tanθsinθ+tanθcosθ=2

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