if-it-s-correct-solve-plz-lim-x-0-x-x-1-xlnx-

Question Number 12328 by Mr Chheang Chantria last updated on 19/Apr/17

if {it}^{'} s correct solve plz

\lim_{x \to 0} \frac{x^{x} - 1}{xlnx}

Answered by mrW1 last updated on 19/Apr/17

= \lim_{x \to 0} \frac{e^{x \ln x} - 1}{x \ln x}

= \lim_{x \to 0} \frac{x^{x} (1 + \ln x)}{1 + \ln x}

= \lim_{x \to 0} x^{x}

= 1

Facebook Tweet Pin