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Question Number 1689 by 123456 last updated on 31/Aug/15
if p and q are two afirmation  ∼(p→q)=?  ∼(p←q)=?  ∼(p⇔q)=?
ifpandqaretwoafirmation(pq)=?(pq)=?(pq)=?
Answered by 112358 last updated on 01/Sep/15
We will use the fact that   p⇒q≡∽p∨q. Therefore,  ∽(p⇒q)≡∽(∽p∨q)                    ≡∽(∽p)∧∽q      De Morgan′s law                    ≡p∧∽q            .      Involution law  Similary,∽(p←q)≡∽(q⇒p)≡q∧∽p .  By definition,               p⇔q≡(p⇒q)∧(q⇒p).  ∴∽(p⇔q)≡∽[(p⇒q)∧(q⇒p)]                       ≡∽(p⇒q)∨∽(q⇒p)                       ≡(p∧∽q)∨(q∧∽p)
Wewillusethefactthatpq≡∽pq.Therefore,(pq)≡∽(pq)≡∽(p)qDeMorganslawpq.InvolutionlawSimilary,(pq)≡∽(qp)qp.Bydefinition,pq(pq)(qp).∴∽(pq)≡∽[(pq)(qp)]≡∽(pq)(qp)(pq)(qp)

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