Question Number 7656 by Tawakalitu. last updated on 07/Sep/16

Commented by prakash jain last updated on 12/Sep/16

Answered by Rasheed Soomro last updated on 09/Sep/16
![S_n =2n^2 +n t_(1002) =? Let a and d are first term and common difference of the AP. S_n =(n/2)[2a+(n−1)d] Let first determine sum of 2003 terms,which will help us to determine t_(1002) . S_(2003) =((2003)/2)[2a+(2003−1)d]=2(2003)^2 +2003 =[2a+2002d]=((2(2003)^2 +2003)/(2003))×2 2[a+1001d]=[2(2003)+1]×2 a+(1002−1)d=(([2(2003)+1]×2)/2)=4006+1=4007 t_(1002) =4007](https://www.tinkutara.com/question/Q7660.png)
Commented by Tawakalitu. last updated on 09/Sep/16

Commented by Rasheed Soomro last updated on 09/Sep/16

Commented by Tawakalitu. last updated on 11/Sep/16

Commented by Tawakalitu. last updated on 11/Sep/16
