Question Number 6604 by WAI LIN last updated on 05/Jul/16

Commented by prakash jain last updated on 05/Jul/16

Commented by WAI LIN last updated on 05/Jul/16

Commented by WAI LIN last updated on 05/Jul/16

Answered by WAI LIN last updated on 05/Jul/16
![∫_0 ^∞ f(x)dx =1 ∫_0 ^∞ c e^(−2x) dx = 1 −(c/2) [e^(−2) ]_0 ^∞ =1 (c/2) =1 ∴c = 2 Next,P(X>2)=∫_2 ^∞ 2 e^(−2x) dx = −[e^(−2x) ]_2 ^∞ = e^(−4)](https://www.tinkutara.com/question/Q6623.png)