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if-the-lcm-and-gcf-of-three-numbers-are-360-and-6-other-numbers-are-18-and-60-Find-the-third-number-I-need-help-plz-




Question Number 72526 by liki last updated on 30/Oct/19
if the lcm and gcf of three numbers   are 360 and 6,other numbers are 18    and 60.Find the third number.          ... I need help plz...
ifthelcmandgcfofthreenumbersare360and6,othernumbersare18and60.Findthethirdnumber.Ineedhelpplz
Commented by TawaTawa last updated on 30/Oct/19
For three numbers       a × b × c  =  ((lcm(a, b, c) × gcd (a, b) × gcd(c, a))/(gcd(a, b, c)))
Forthreenumbersa×b×c=lcm(a,b,c)×gcd(a,b)×gcd(c,a)gcd(a,b,c)
Answered by mind is power last updated on 30/Oct/19
gcd(a,b,c)=d  d∣a,b  d∣c  d⇒∣gcd(a,b),c⇒d∣gcd((gcd(a,b),c)  gcd((gcd(a,b),c)=d⇒d∣c  d∣gcd(a,b)⇒d∣a&d∣b  ⇒gcd(a,b,c)=gcd(gcd(a,b),c)  lcm(a,b,c)=lcm(lcm(a,b),c))  m=lcm(a,b,c)⇒a∣m,b∣m⇒lcm(a,b)∣m  c∣m⇒lcm(lcm(a,b),c)∣m  d=lcm(lcm(a,b),c)⇒c∣d,lcm(a,b)∣d⇒a∣d,b∣d,c∣d⇒lcm(a,b,c)∣d  ⇔lcm(lcm(a,b),c)=lcm(a,b,c)  after that a,b,c three number  lcm(a,b,c)=360  gcd(a,b,c)=18  a=6,b=18  ⇔ { ((lcm(6,18,c)=360=lcm(lcm(18,60),c)=360)),((gcd(60,18,c)=6=gcd(gcd(60,18),c)=6)) :}  lcm(60,18)=6lcm(10,3)=180,gcd(60,18)=6  ⇒lcm(180,c)=360  ⇒gcd(6,c)=6  c=6k⇒gcd(6,6k)=6=6gcd(k,1)=6  lcm(180,6k)=360  6lcm(30,k)=360  lcm(30,k)=60=((30.k)/(gcd(30,k)))⇒2gcd(30,k) =k  gcd(30,k)∈{1,2,3,5,6,10,15,30}  =1⇒k=2   no  gcd=2⇒k=4 ⇒  gcd=3⇒k=6 but gcd(6,30)=6  no  gcd=5⇒k=10 gcd(10,30)=10 no  gcd=6⇒k=12   gcd=10⇒k=20   gcd=15⇒k=30 non  gcd=30⇒k=60  k∈{4,20,60,12}  c=6k  c∈{360,120,24,72}
gcd(a,b,c)=dda,bdcd⇒∣gcd(a,b),cdgcd((gcd(a,b),c)gcd((gcd(a,b),c)=ddcdgcd(a,b)da&dbgcd(a,b,c)=gcd(gcd(a,b),c)lcm(a,b,c)=lcm(lcm(a,b),c))m=lcm(a,b,c)am,bmlcm(a,b)mcmlcm(lcm(a,b),c)md=lcm(lcm(a,b),c)cd,lcm(a,b)dad,bd,cdlcm(a,b,c)dlcm(lcm(a,b),c)=lcm(a,b,c)afterthata,b,cthreenumberlcm(a,b,c)=360gcd(a,b,c)=18a=6,b=18{lcm(6,18,c)=360=lcm(lcm(18,60),c)=360gcd(60,18,c)=6=gcd(gcd(60,18),c)=6lcm(60,18)=6lcm(10,3)=180,gcd(60,18)=6lcm(180,c)=360gcd(6,c)=6c=6kgcd(6,6k)=6=6gcd(k,1)=6lcm(180,6k)=3606lcm(30,k)=360lcm(30,k)=60=30.kgcd(30,k)2gcd(30,k)=kgcd(30,k){1,2,3,5,6,10,15,30}=1k=2nogcd=2k=4gcd=3k=6butgcd(6,30)=6nogcd=5k=10gcd(10,30)=10nogcd=6k=12gcd=10k=20gcd=15k=30nongcd=30k=60k{4,20,60,12}c=6kc{360,120,24,72}
Commented by liki last updated on 30/Oct/19
thanks sir..
thankssir..
Commented by mind is power last updated on 30/Oct/19
y′re welcom
yrewelcom
Commented by mr W last updated on 30/Oct/19
24 and 72 also ok
24and72alsook
Commented by mind is power last updated on 30/Oct/19
yes i fixed i took 6 but[the two number are 18,60 not 18 and 6  lol
yesifixeditook6but[thetwonumberare18,60not18and6lol
Answered by mr W last updated on 30/Oct/19
LCM=360=2^3 ×3^2 ×5^1   GCD=6=2^1 ×3^1   A=18=2^1 ×3^2   B=60=2^2 ×3^1 ×5^1   C=2^3 ×3^(1...2) ×5^(0...1)   =8×3=24  =8×3×5=120  =8×9=72  =8×9×5=360
LCM=360=23×32×51GCD=6=21×31A=18=21×32B=60=22×31×51C=23×312×501=8×3=24=8×3×5=120=8×9=72=8×9×5=360
Commented by TawaTawa last updated on 30/Oct/19
Sir help me check the question i solved in Q72560  if i am correct
SirhelpmecheckthequestionisolvedinQ72560ifiamcorrect
Commented by liki last updated on 31/Oct/19
•Thank you sir
Thankyousir

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