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if-x-2-5x-9-0-then-x-




Question Number 2304 by Ashis last updated on 14/Nov/15
if  x^2 +5x−9= 0  then x=?
$${if}\:\:{x}^{\mathrm{2}} +\mathrm{5}{x}−\mathrm{9}=\:\mathrm{0}\:\:{then}\:{x}=? \\ $$
Answered by prakash jain last updated on 14/Nov/15
x^2 +5x−9  x=((−5±(√((−5)^2 −4(1)(−9))))/(2×(1)))=((−5±(√(61)))/2)
$${x}^{\mathrm{2}} +\mathrm{5}{x}−\mathrm{9} \\ $$$${x}=\frac{−\mathrm{5}\pm\sqrt{\left(−\mathrm{5}\right)^{\mathrm{2}} −\mathrm{4}\left(\mathrm{1}\right)\left(−\mathrm{9}\right)}}{\mathrm{2}×\left(\mathrm{1}\right)}=\frac{−\mathrm{5}\pm\sqrt{\mathrm{61}}}{\mathrm{2}} \\ $$

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