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If-you-have-a-real-continuous-function-f-x-If-you-take-a-distance-between-f-x-and-f-x-1-what-is-the-average-distance-within-a-x-b-




Question Number 6610 by Temp last updated on 05/Jul/16
If you have a real continuous function f(x),  If you take a distance between  f(x) and f(x+1), what is the average  distance within a≤x≤b?
Ifyouhavearealcontinuousfunctionf(x),Ifyoutakeadistancebetweenf(x)andf(x+1),whatistheaveragedistancewithinaxb?
Commented by Temp last updated on 05/Jul/16
let the distance be:  d=(√(∣f(x+1)−f(x)∣^2 +∣(x+1)−x∣^2 ))  d=(√(∣f(x+1)−f(x)∣^2 +1))
letthedistancebe:d=f(x+1)f(x)2+(x+1)x2d=f(x+1)f(x)2+1
Commented by Yozzii last updated on 05/Jul/16
d_(avg) =(1/(b−a))∫_a ^b d dx  d_(avg) =(1/(b−a))∫_a ^b (√((f(x+1)−f(x))^2 +1)) dx
davg=1baabddxdavg=1baab(f(x+1)f(x))2+1dx
Commented by Temp last updated on 05/Jul/16
I thought so, thank you!
Ithoughtso,thankyou!
Commented by Temp last updated on 05/Jul/16
is it (f(x+1)−f(x))^2   or  ∣f(x+1)−f(x)∣^2   ??
isit(f(x+1)f(x))2orf(x+1)f(x)2??
Commented by Yozzii last updated on 05/Jul/16
They are expressions equal in value  so either notation is appropriate.   I was taught that formula using parentheses.
Theyareexpressionsequalinvaluesoeithernotationisappropriate.Iwastaughtthatformulausingparentheses.

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