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Question Number 140107 by EnterUsername last updated on 04/May/21
If z_1 , z_2 , and z_3  are the vertices of an equilateral triangle  described in counterclock sense and w≠1 is a cube root  of unity, then  (A) z_1 −z_3 =(z_3 −z_2 )w  (B) z_1 +z_2 w+z_3 w^2 =0  (C) (1/(z_1 −z_2 ))+(1/(z_2 −z_3 ))+(1/(z_3 −z_1 ))=0  (D) z_1 ^2 +z_2 ^2 +z_3 ^2 =z_1 z_2 +z_2 z_3 +z_3 z_1
Ifz1,z2,andz3aretheverticesofanequilateraltriangledescribedincounterclocksenseandw1isacuberootofunity,then(A)z1z3=(z3z2)w(B)z1+z2w+z3w2=0(C)1z1z2+1z2z3+1z3z1=0(D)z12+z22+z32=z1z2+z2z3+z3z1

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