In-a-right-triangle-the-mid-point-of-the-hypotenuse-is-equidistant-from-all-the-three-vertices-of-the-triangle-

Question Number 4579 by Rasheed Soomro last updated on 08/Feb/16

$${In}\:{a}\:{right}\:{triangle},\:{the}\:{mid}-{point}\:{of}\:{the} \\ $$$${hypotenuse}\:{is}\:{equidistant}\:{from}\:{all}\:{the} \\ $$$${three}\:{vertices}\:{of}\:{the}\:{triangle}. \\ $$

Commented by Yozzii last updated on 08/Feb/16

$${Prove}\:{this}\:{theorem}? \\ $$

Commented by Rasheed Soomro last updated on 09/Feb/16

$${Yes}. \\ $$

Answered by Yozzii last updated on 12/Feb/16

Commented by Yozzii last updated on 13/Feb/16

$${I}\:{should}\:{have}\:{specified}\:{that}\:{L}\: \\ $$$${respresents}\:{the}\:{perpendicular}\:{bisector} \\ $$$${of}\:{AB}. \\ $$

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