Question Number 9800 by richard last updated on 05/Jan/17
$$\mathrm{is}\:\mathrm{there}\:\mathrm{a}\:\mathrm{value}\:\mathrm{for}\:\mathrm{tg}^{\mathrm{2}} \frac{\pi}{\mathrm{4}}\:\:? \\ $$
Commented by FilupSmith last updated on 05/Jan/17
$${tg}^{\mathrm{2}} \frac{\pi}{\mathrm{4}}={tg}^{\mathrm{2}} \frac{\pi}{\mathrm{4}} \\ $$$$\: \\ $$$$\mathrm{unless}\:{t}\:\mathrm{and}\:{g}\:\mathrm{have}\:\mathrm{values},\:\mathrm{you}\:\mathrm{can} \\ $$$$\mathrm{no}\:\mathrm{further}\:\mathrm{evaluate} \\ $$
Commented by geovane10math last updated on 06/Jan/17
$$\mathrm{tg}\:=\:\mathrm{tan}\: \\ $$
Answered by sandy_suhendra last updated on 05/Jan/17
$$\mathrm{do}\:\mathrm{you}\:\mathrm{mean}\:\mathrm{tg}\:=\:\mathrm{tan}? \\ $$$$\mathrm{tan}^{\mathrm{2}} \:\frac{\pi}{\mathrm{4}}=\left(\mathrm{tan}\:\frac{\pi}{\mathrm{4}}\right)^{\mathrm{2}} \:=\:\mathrm{1}^{\mathrm{2}} \:=\:\mathrm{1} \\ $$