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jika-fungsi-f-x-px-2-p-1-x-6-mencapai-nilai-tertingi-untuk-x-1-maka-nilai-p-




Question Number 985 by tera last updated on 13/May/15
jika fungsi f(x)= px^2 −(p+1)x−6  mencapai nilai tertingi untuk   x=−1. maka nilai p=.....℧
jikafungsif(x)=px2(p+1)x6mencapainilaitertingiuntukx=1.makanilaip=..
Answered by prakash jain last updated on 13/May/15
f ′(x)=2px−(p+1), f ′′(x)=2p  f ′(−1)=0⇒−2p−p−1=0⇒p=−(1/3)  If p=−(1/3), f ′(−1)=0, f ′′(−1)=−(2/3)<0
f(x)=2px(p+1),f(x)=2pf(1)=02pp1=0p=13Ifp=13,f(1)=0,f(1)=23<0

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