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k-1-k-3-2k-k-2-6k-9-




Question Number 135682 by liberty last updated on 15/Mar/21
Σ_(k=1) ^∞  ((k^3 +2k)/(k^2 +6k+9)) =?
$$\underset{{k}=\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{{k}^{\mathrm{3}} +\mathrm{2}{k}}{{k}^{\mathrm{2}} +\mathrm{6}{k}+\mathrm{9}}\:=? \\ $$
Answered by abdullahoudou last updated on 15/Mar/21
∞
$$\infty \\ $$
Answered by dhgt last updated on 04/May/21

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